reflect.py 文件源码

def filenameToModuleName(fn):
    """Convert a name in the filesystem to the name of the Python module it is.

    This is agressive about getting a module name back from a file; it will
    always return a string.  Agressive means 'sometimes wrong'; it won't look
    at the Python path or try to do any error checking: don't use this method
    unless you already know that the filename you're talking about is a Python
    module.
    """
    fullName = os.path.abspath(fn)
    modName = os.path.splitext(os.path.basename(fn))[0]
    while 1:
        fullName = os.path.dirname(fullName)
        if os.path.exists(os.path.join(fullName, "__init__.py")):
            modName = "%s.%s" % (os.path.basename(fullName), modName)
        else:
            break
    return modName

#boo python