utils.py 文件源码

def previous_current_next(items):
    """
    From http://www.wordaligned.org/articles/zippy-triples-served-with-python

    Creates an iterator which returns (previous, current, next) triples,
    with ``None`` filling in when there is no previous or next
    available.
    """
    extend = itertools.chain([None], items, [None])
    prev, cur, nex = itertools.tee(extend, 3)
    # Advancing an iterator twice when we know there are two items (the
    # two Nones at the start and at the end) will never fail except if
    # `items` is some funny StopIteration-raising generator. There's no point
    # in swallowing this exception.
    next(cur)
    next(nex)
    next(nex)
    return zip(prev, cur, nex)