actionform.py 文件源码

def upload(url, filename=None):
    from urllib.request import Request, urlopen
    from urllib.parse import urlsplit
    import shutil
    def getFilename(url,openUrl):
        if 'Content-Disposition' in openUrl.info():
            # If the response has Content-Disposition, try to get filename from it
            cd = dict([x.strip().split('=') if '=' in x else (x.strip(),'')
                                        for x in openUrl.info().split(';')])
            if 'filename' in cd:
                fname = cd['filename'].strip("\"'")
                if fname: return fname
        # if no filename was found above, parse it out of the final URL.
        return os.path.basename(urlsplit(openUrl.url)[2])
    r = urlopen(Request(url))
    success = None
    try:
        filename = filename or "/tmp/%s" % getFilename(url,r)
        with open(filename, 'wb') as f:
            shutil.copyfileobj(r,f)
        success = filename
    finally:
        r.close()
    return success