core.py 文件源码

def scale(X, n):
    Xn = unfold(X, n)
    m = np.float_(np.sqrt((Xn ** 2).sum(axis=1)))
    m[m == 0] = 1
    for i in range(Xn.shape[0]):
        Xn[i, :] = Xn[i] / m[i]
    return fold(Xn, n, X.shape)


# TODO more efficient cython implementation