Radiation.py 文件源码

python
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项目:und_Sophie_2016 作者: SophieTh 项目源码 文件源码
def integration(self,is_quadrant=0,use_flux_per_mrad2_or_mm2=1):
        if (self.X is None or self.Y is None):
            raise Exception(" X and Y must be array for integration")
        if self.X.shape != self.Y.shape:
            raise Exception(" X and Y must have the same shape")

        if len(self.X.shape)==2 :
            X = np.linspace(self.X.min(), self.X.max(), self.X.shape[0])
            Y = np.linspace(self.Y.min(), self.Y.max(), self.Y.shape[1])

            res1=integrate.trapz(self.intensity, X)
            res = integrate.trapz(res1, Y)

            # res = integrate.simps(integrate.simps(self.intensity, X), Y)

            # res = self.intensity.sum() * (self.X[1,0] - self.X[0,0]) * (self.Y[0,1] - self.X[0,0]) # regular grid only
        else : # X and Y are 1d array
            if len(self.X) == 1:
                res = self.intensity[0]
            else: # choix arbitraire
                XY = np.zeros_like(self.X)
                for i in range(1, len(self.X)):
                    XY[i] = XY[i-1]+np.sqrt((self.X[i] - self.X[i-1]) * 2 + (self.Y[i] - self.Y[i-1]) ** 2)
                res = np.trapz(self.intensity, XY)

        # Note that the value of flux is in phot/s/0.1%bw/mrad2 (or .../mm2) and
        # our grid is in rad (or m), therefore we must account for this:
        if use_flux_per_mrad2_or_mm2:
            res *= 1e6

        # in case the calculation is for a quadrant, the integral is four times the calculated value
        if is_quadrant:
            res *= 4
        return res
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