invalid_cnpj_cpf_classifier.py 文件源码

def predict(self, dataframe):
        def is_invalid(row):
            valid_cpf = cpf.validate(str(row['recipient_id']).zfill(11))
            valid_cnpj = cnpj.validate(str(row['recipient_id']).zfill(14))
            good_doctype = row['document_type'] in ('bill_of_sale', 'simple_receipt', 'unknown')
            return good_doctype and (not (valid_cpf or valid_cnpj))
        return np.r_[dataframe.apply(is_invalid, axis=1)]