position_hand.py 文件源码

def vector_product(v0, v1, axis=0):
    """Return vector perpendicular to vectors.

    >>> v = vector_product([2, 0, 0], [0, 3, 0])
    >>> numpy.allclose(v, [0, 0, 6])
    True
    >>> v0 = [[2, 0, 0, 2], [0, 2, 0, 2], [0, 0, 2, 2]]
    >>> v1 = [[3], [0], [0]]
    >>> v = vector_product(v0, v1)
    >>> numpy.allclose(v, [[0, 0, 0, 0], [0, 0, 6, 6], [0, -6, 0, -6]])
    True
    >>> v0 = [[2, 0, 0], [2, 0, 0], [0, 2, 0], [2, 0, 0]]
    >>> v1 = [[0, 3, 0], [0, 0, 3], [0, 0, 3], [3, 3, 3]]
    >>> v = vector_product(v0, v1, axis=1)
    >>> numpy.allclose(v, [[0, 0, 6], [0, -6, 0], [6, 0, 0], [0, -6, 6]])
    True

    """
    return numpy.cross(v0, v1, axis=axis)