p2p.py 文件源码

def get_good_peers(self, max_count):
        t = time.time()
        return [x[0] for x in sorted(self.addr_store.iteritems(), key=lambda (k, (services, first_seen, last_seen)):
            -math.log(max(3600, last_seen - first_seen))/math.log(max(3600, t - last_seen))*random.expovariate(1)
        )][:max_count]