def test_string_boundaries(self):
# See http://bugs.python.org/issue10713
self.assertEqual(re.search(r"\b(abc)\b", "abc").group(1),
"abc")
# There's a word boundary at the start of a string.
self.assertTrue(re.match(r"\b", "abc"))
# A non-empty string includes a non-boundary zero-length match.
self.assertTrue(re.search(r"\B", "abc"))
# There is no non-boundary match at the start of a string.
self.assertFalse(re.match(r"\B", "abc"))
# However, an empty string contains no word boundaries, and also no
# non-boundaries.
self.assertIsNone(re.search(r"\B", ""))
# This one is questionable and different from the perlre behaviour,
# but describes current behavior.
self.assertIsNone(re.search(r"\b", ""))
# A single word-character string has two boundaries, but no
# non-boundary gaps.
self.assertEqual(len(re.findall(r"\b", "a")), 2)
self.assertEqual(len(re.findall(r"\B", "a")), 0)
# If there are no words, there are no boundaries
self.assertEqual(len(re.findall(r"\b", " ")), 0)
self.assertEqual(len(re.findall(r"\b", " ")), 0)
# Can match around the whitespace.
self.assertEqual(len(re.findall(r"\B", " ")), 2)
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