file_management.py 文件源码

def create_text_file(name):
    """
    Create a new text file, change its name and return it
    Args:
    - name, the name of the text file, a string"""
    if not name and isinstance(name, str):
        raise TypeError('The name of the text file has to be a string')

    bpy.ops.text.new()
    import re
    re_text = re.compile(r'^Text.[0-9]{3}$')

    text_name = ''
    text_index, max_index = 0, 0
    for text in bpy.data.texts:
        if re_text.match(text.name):
            text_index = int(text.name[-3:])
            if text_index > max_index:
                max_index = text_index
                text_name = text.name
    if not text_name:
        text_name = 'Text'

    bpy.data.texts[text_name].name = name
    return bpy.data.texts[name]