def cpu_count_physical():
"""Return the number of physical CPUs in the system."""
# From the C module we'll get an XML string similar to this:
# http://manpages.ubuntu.com/manpages/precise/man4/smp.4freebsd.html
# We may get None in case "sysctl kern.sched.topology_spec"
# is not supported on this BSD version, in which case we'll mimic
# os.cpu_count() and return None.
ret = None
s = cext.cpu_count_phys()
if s is not None:
# get rid of padding chars appended at the end of the string
index = s.rfind("</groups>")
if index != -1:
s = s[:index + 9]
root = ET.fromstring(s)
try:
ret = len(root.findall('group/children/group/cpu')) or None
finally:
# needed otherwise it will memleak
root.clear()
if not ret:
# If logical CPUs are 1 it's obvious we'll have only 1
# physical CPU.
if cpu_count_logical() == 1:
return 1
return ret
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