GraphParser.java 文件源码

java
阅读 25 收藏 0 点赞 0 评论 0

项目:digraph-parser 作者:
@Override
public void reportInputMismatch(Parser recognizer, InputMismatchException e) throws RecognitionException {
    String msg = "mismatched input " + getTokenErrorDisplay(e.getOffendingToken());
    msg += " expecting one of " + e.getExpectedTokens().toString(recognizer.getTokenNames());
    RecognitionException ex = new RecognitionException(msg, recognizer, recognizer.getInputStream(), recognizer.getContext());
    ex.initCause(e);
    throw ex;
}
评论列表
文章目录


问题


面经


文章

微信
公众号

扫码关注公众号