匿名网友
1. 将数字进行翻转,如输入1234,输入4321,需考虑是负数的情况
public class FanZhuan {
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
boolean isNegative = false;
int i = scanner.nextInt();
scanner.close();
if (i <0) {//判断是否是负数
i = -i;
isNegative = true;
}
String string = "";
while(i!=0){
string += i%10;//每次取余数,拼接上
i = i/10;
}
int a = Integer.parseInt(string);//在转换成int型
System.out.println(isNegative ? -a : a);
}
}
2. 输入一个字符串，输出重复的字符
public class RepeatOut {
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
String string = scanner.next();
scanner.close();
char a [ ] = string.toCharArray();
int b [ ] = new int[26*2];
for (int i = 0; i < a.length; i++) {
if ( b[a[i]-65] == 1) {
System.out.print(a[i]);
b[a[i]-65]++;
}else if(b[a[i]-65] == 0){
b[a[i]-65]++;
}
}
}
}
3. 将输入的字符串中的数字进行排序,例如,输入29shf23 ,输出2239
public class SortNum {
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
String string = scanner.nextLine();
ArrayList
scanner.close();
for (int i = 0; i < string.length(); i++) {
char ch = string.charAt(i);//依次取出每个字符
if (Character.isDigit(ch)) {//判断是否是数字
arrayList.add(string.charAt(i) + "");//用ArrayList总感觉大材小用了,好浪费呀.
}
}
Collections.sort(arrayList);//排序
for (int i = 0; i < arrayList.size(); i++) {
System.out.print( arrayList.get(i) );
}
}
}
4. 字符串中挑数字并排序， 输入: abzxcd12efgdhi543fexy，输出: 12345
public class TiaoNumAndSort {
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
// System.out.println("请输入字符串:");
String string = scanner.nextLine();
scanner.close();
String s = "";
for (int i = 0; i < string.length(); i++) {//先把数组取出来并拼接到成一个字符串
char c = string.charAt(i);
if( !(c >=’A’ && c<='z') ){
s +=c;
}
}
char b[] = s.toCharArray();//将数字字符串转成数组
char tmp;
for (int i = 0; i < b.length; i++) {
for (int j = i+1; j < b.length; j++) {
if(b[i]>b[j]){
tmp = b[i];
b[i] = b[j];
b[j] = tmp;
}
}
}
for (int i = 0; i < b.length; i++) { System.out.print(b[i]); } } } 5. Lily上课时使用字母数字图片教小朋友们学习英语单词，每次都需要把这些图片按照大小（ASCII码值从小到大）排列收好。请大家给Lily帮忙输入: Lily使用的图片包括"A"到"Z"、"a"到"z"、"0"到"9"。输入字母或数字个数不超过1024。输出 Lily的所有图片按照从小到大的顺序输出样例输入 Ihave1nose2hands10fingers 样例输出 0112Iaadeeefghhinnnorsssv public class ZhengLi { public static void main(String[] args) { Scanner scanner = new Scanner(System.in); String s = scanner.nextLine(); scanner.close(); char m[] = s.toCharArray(); int a[] = new int[10]; int b[] = new int[36*2]; for (int i = 0; i < m.length; i++) { if( ('0' <= m[i]) && (m[i] <= '9') ){ a[m[i]-48]++; }else { b[m[i]-65]++; } } for (int i = 0; i < a.length; i++) { for (int j = 0; j < a[i]; j++) { System.out.print( (char)(i+48) ); } } for (int i = 0; i < b.length; i++) { for (int j = 0; j < b[i]; j++) { System.out.print( (char)(i+65) ); } } } } 6. 输出一个字符串最后一个单词的长度。 public class ZiFuChuan { public static void main(String[] args) { Scanner scanner = new Scanner(System.in); String s = scanner.nextLine(); scanner.close(); String a[] = s.split(" "); String b = a[a.length-1]; System.out.println(b.length()); } }
